Sheep: Sheep!

1:
‖〈1,1〉‖²:
lim x->0 x/(√(2x+9)-3):
φ(12):
₁∫^∞ 10/x³dx:
⅛ _n=1∏⁴ n!!:
π⁶/135ζ(6):
<1,2,2>∙(<2,0,1>×<3,2,1>):
a₁=3,a₂=1,a_n+1=a_n+a_n-1; a₅:
(1+i)(-1-i)(1-2i)(-2+i):
(cos(π/5)/(cos(π/12)cos(5π/12))-1)²+8cos²(π/6):
1/(Res(-1/(z³+8i),2i)):
8sec²(arctan(cos(arctan(cos(arctan(cos(arctan(cos(arctan(cos(0))))))))))):
C₄:
10103_2i:

1

2

3

4

5

Assuming !! means the double factorial and not the factorial taken twice: 6

Sloppy notation. I'm guessing what you meant was π⁶/(135*ζ(6)), in which case it would be 7

8. Fuck the cross product.

9

10

11 Wait, cos(π/5) = φ/2? What? Holy shit!

This is the only one I don't know how to solve. I could Wolfram it, but ehh.

Fuck you, I'm definitely Wolframing this one. I know how to solve it, but there's no way I can be bothered to. 13

4 real and 4 complex dimensions, or ~262 Hz (Not entirely sure how you'd get "14" out of this one, unless you meant to write E₁₆ or something. I'm pretty sure "C" isn't a number in base 4.)

16 Base i is a good idea.