RE: The 2am thread
11-21-2016, 10:22 AM
ughh why are halfway functions so difficult to compute
if f(x) = x^2, then f^(1/2)(x) is clearly just x^root 2. in fact, f^(a/b)(x)=x^2^(a/b). you can even replace 2 with any whole number and probably any real number but i'm too tired to check. but the moment you set f(x)=x^2 + 1 it becomes like a million times more difficult. f(x)=x^2 +x is probably like computationally impossible or some shit. and even f^(0.5)(x)=x^root 2 doesn't really work with negative or complex numbers.
why do i defualt to doing math when im tired, this is not ideal. i can barely think.
if f(x) = x^2, then f^(1/2)(x) is clearly just x^root 2. in fact, f^(a/b)(x)=x^2^(a/b). you can even replace 2 with any whole number and probably any real number but i'm too tired to check. but the moment you set f(x)=x^2 + 1 it becomes like a million times more difficult. f(x)=x^2 +x is probably like computationally impossible or some shit. and even f^(0.5)(x)=x^root 2 doesn't really work with negative or complex numbers.
why do i defualt to doing math when im tired, this is not ideal. i can barely think.
![[Image: egg006.png?raw=1]](https://www.dropbox.com/s/xirjasxjrie6qdn/egg006.png?raw=1)
![[Image: Gou1RJu.png]](https://i.imgur.com/Gou1RJu.png)