RE: wonderings
03-16-2017, 03:16 AM
I think that provided there is some open interval (xn-δ,xn+δ) in which every point had been mapped to the continuous and differentiable function after uncountably many steps, then the function at xn would be continuous and differentiable.
The problem is that any function fn(x) does not fit this criterion, because you are going one point at a time, so it's a countably infinite number, so we can do a diagonal proof to find a point however close to xn that is still 0, and so at no time would it be continuous.
The problem is that any function fn(x) does not fit this criterion, because you are going one point at a time, so it's a countably infinite number, so we can do a diagonal proof to find a point however close to xn that is still 0, and so at no time would it be continuous.