RE: Post making contest
07-10-2016, 01:29 AM
(This post was last modified: 07-10-2016, 01:30 AM by qwerx3.)
∑n=0∞(⌈∫04 x/(x2+x+2) dx⌉)π n2/2n-1 = ∑n=0∞(1)π n2/2n-1 = ∑n=0∞ n2/2n-1 = ∑n=0∞ ((n+1)C2+((n)C2))/2n-1 = (3/2)*∑n=0∞ ((n+1)C2)/2n-1 = (3/2)*(∑n=0∞ 1/2n)3 = 3/2*(2)3=3/2*8=12